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+(************************************************************************)
+(* v * The Coq Proof Assistant / The Coq Development Team *)
+(* <O___,, * CNRS-Ecole Polytechnique-INRIA Futurs-Universite Paris Sud *)
+(* \VV/ **************************************************************)
+(* // * This file is distributed under the terms of the *)
+(* * GNU Lesser General Public License Version 2.1 *)
+(************************************************************************)
+
+Require Import Peano_dec Compare_dec
+ DecidableType2 OrderedType2 OrderedType2Facts.
+
+
+(** * DecidableType structure for Peano numbers *)
+
+Module Nat_as_MiniDT <: MiniDecidableType.
+ Definition t := nat.
+ Definition eq_dec := eq_nat_dec.
+End Nat_as_MiniDT.
+
+Module Nat_as_DT <: UsualDecidableType := Make_UDT Nat_as_MiniDT.
+
+(** Note that [Nat_as_DT] can also be seen as a [DecidableType]
+ and a [DecidableTypeOrig]. *)
+
+
+
+(** * OrderedType structure for Peano numbers *)
+
+Module Nat_as_OT <: OrderedTypeFull.
+ Include Nat_as_DT.
+ Definition lt := lt.
+ Definition le := le.
+ Definition compare := nat_compare.
+
+ Instance lt_strorder : StrictOrder lt.
+ Proof. split; [ exact Lt.lt_irrefl | exact Lt.lt_trans ]. Qed.
+
+ Instance lt_compat : Proper (Logic.eq==>Logic.eq==>iff) lt.
+ Proof. repeat red; intros; subst; auto. Qed.
+
+ Lemma le_lteq : forall x y, x <= y <-> x < y \/ x=y.
+ Proof. intuition; subst; auto using Lt.le_lt_or_eq. Qed.
+
+ Lemma compare_spec : forall x y, Cmp eq lt x y (compare x y).
+ Proof.
+ intros; unfold compare.
+ destruct (nat_compare x y) as [ ]_eqn; constructor.
+ apply nat_compare_eq; auto.
+ apply nat_compare_Lt_lt; auto.
+ apply nat_compare_Gt_gt; auto.
+ Qed.
+
+End Nat_as_OT.
+
+(* Note that [Nat_as_OT] can also be seen as a [UsualOrderedType]
+ and a [OrderedType] (and also as a [DecidableType]). *)
+
+
+
+(** * An [order] tactic for Peano numbers *)
+
+Module NatOrder := OTF_to_OrderTac Nat_as_OT.
+Ltac nat_order :=
+ change (@eq nat) with NatOrder.OrderElts.eq in *;
+ NatOrder.order.
+
+(** Note that [nat_order] is domain-agnostic: it will not prove
+ [1<=2] or [x<=x+x], but rather things like [x<=y -> y<=x -> x=y]. *)
+