From 84895f1a210d0037a86887f0f647570bdf40afa2 Mon Sep 17 00:00:00 2001
From: Damien George
Date: Mon, 27 Nov 2017 12:51:52 +1100
Subject: py/parsenum: Improve parsing of floating point numbers.

This patch improves parsing of floating point numbers by converting all the
digits (integer and fractional) together into a number 1 or greater, and
then applying the correct power of 10 at the very end.  In particular the
multiple "multiply by 0.1" operations to build a fraction are now combined
together and applied at the same time as the exponent, at the very end.

This helps to retain precision during parsing of floats, and also includes
a check that the number doesn't overflow during the parsing.  One benefit
is that a float will have the same value no matter where the decimal point
is located, eg 1.23 == 123e-2.
---
 tests/float/float_parse.py | 22 ++++++++++++++++++++++
 1 file changed, 22 insertions(+)
 create mode 100644 tests/float/float_parse.py

(limited to 'tests/float/float_parse.py')

diff --git a/tests/float/float_parse.py b/tests/float/float_parse.py
new file mode 100644
index 000000000..448eff3bc
--- /dev/null
+++ b/tests/float/float_parse.py
@@ -0,0 +1,22 @@
+# test parsing of floats
+
+inf = float('inf')
+
+# it shouldn't matter where the decimal point is if the exponent balances the value
+print(float('1234') - float('0.1234e4'))
+print(float('1.015625') - float('1015625e-6'))
+
+# very large integer part with a very negative exponent should cancel out
+print(float('9' * 60 + 'e-60'))
+print(float('9' * 60 + 'e-40'))
+print(float('9' * 60 + 'e-20') == float('1e40'))
+
+# many fractional digits
+print(float('.' + '9' * 70))
+print(float('.' + '9' * 70 + 'e20'))
+print(float('.' + '9' * 70 + 'e-50') == float('1e-50'))
+
+# tiny fraction with large exponent
+print(float('.' + '0' * 60 + '1e10') == float('1e-51'))
+print(float('.' + '0' * 60 + '9e25'))
+print(float('.' + '0' * 60 + '9e40'))
-- 
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