(************************************************************************) (* v * The Coq Proof Assistant / The Coq Development Team *) (* cut (a=a'); [cg|r] | |- ?f ?a ?b = ?f' ?a' ?b' => cut (b=b');[cut (a=a');[cg|r]|r] | |- ?f ?a ?b ?c = ?f' ?a' ?b' ?c'=> cut (c=c');[cut (b=b');[cut (a=a');[cg|r]|r]|r] | |- ?f ?a ?b ?c ?d= ?f' ?a' ?b' ?c' ?d'=> cut (d=d');[cut (c=c');[cut (b=b');[cut (a=a');[cg|r]|r]|r]|r] | |- ?f ?a ?b ?c ?d ?e= ?f' ?a' ?b' ?c' ?d' ?e'=> cut (e=e');[cut (d=d');[cut (c=c');[cut (b=b');[cut (a=a');[cg|r]|r]|r]|r]|r] | |- ?f ?a ?b ?c ?d ?e ?g= ?f' ?a' ?b' ?c' ?d' ?e' ?g' => cut (f=f');[cut (e=e');[cut (d=d');[cut (c=c');[cut (b=b');[cut (a=a');[cg|r]|r]|r]|r]|r]|r] | _ => idtac end. (* Rewriting in all hypothesis several times everywhere *) Tactic Notation "rewrite_all" constr(eq) := repeat rewrite eq in *. Tactic Notation "rewrite_all" "<-" constr(eq) := repeat rewrite <- eq in *. (* Keeping a copy of an expression *) Ltac remembertac x a := let x := fresh x in let H := fresh "Heq" x in (set (x:=a) in *; assert (H: x=a) by reflexivity; clearbody x). Tactic Notation "remember" constr(c) "as" ident(x) := remembertac x c. (** Tactics for applying equivalences. The following code provides tactics "apply -> t", "apply <- t", "apply -> t in H" and "apply <- t in H". Here t is a term whose type consists of nested dependent and nondependent products with an equivalence A <-> B as the conclusion. The tactics with "->" in their names apply A -> B while those with "<-" in the name apply B -> A. *) (* The idea of the tactics is to first provide a term in the context whose type is the implication (in one of the directions), and then apply it. The first idea is to produce a statement "forall ..., A -> B" (call this type T) and then do "assert (H : T)" for a fresh H. Thus, T can be proved from the original equivalence and then used to perform the application. However, currently in Ltac it is difficult to produce such T from the original formula. Therefore, we first pose the original equivalence as H. If the type of H is a dependent product, we create an existential variable and apply H to this variable. If the type of H has the form C -> D, then we do a cut on C. Once we eliminate all products, we split (i.e., destruct) the conjunction into two parts and apply the relevant one. *) Ltac find_equiv H := let T := type of H in lazymatch T with | ?A -> ?B => let H1 := fresh in let H2 := fresh in cut A; [intro H1; pose proof (H H1) as H2; clear H H1; rename H2 into H; find_equiv H | clear H] | forall x : ?t, _ => let a := fresh "a" with H1 := fresh "H" in evar (a : t); pose proof (H a) as H1; unfold a in H1; clear a; clear H; rename H1 into H; find_equiv H | ?A <-> ?B => idtac | _ => fail "The given statement does not seem to end with an equivalence" end. Ltac bapply lemma todo := let H := fresh in pose proof lemma as H; find_equiv H; [todo H; clear H | .. ]. Tactic Notation "apply" "->" constr(lemma) := bapply lemma ltac:(fun H => destruct H as [H _]; apply H). Tactic Notation "apply" "<-" constr(lemma) := bapply lemma ltac:(fun H => destruct H as [_ H]; apply H). Tactic Notation "apply" "->" constr(lemma) "in" ident(J) := bapply lemma ltac:(fun H => destruct H as [H _]; apply H in J). Tactic Notation "apply" "<-" constr(lemma) "in" ident(J) := bapply lemma ltac:(fun H => destruct H as [_ H]; apply H in J). (** A tactic simpler than auto that is useful for ending proofs "in one step" *) Tactic Notation "now" tactic(t) := t; match goal with | H : _ |- _ => solve [inversion H] | _ => solve [trivial | reflexivity | symmetry; trivial | discriminate | split] | _ => fail 1 "Cannot solve this goal" end.