From 2ed6aeb03fc0e25a47223189d8444cbb6b749f2d Mon Sep 17 00:00:00 2001
From: letouzey
Date: Thu, 5 Jul 2012 22:51:11 +0000
Subject: Legacy Ring and Legacy Field migrated to contribs

 One slight point to check someday : fourier used to
 launch a tactic called Ring.polynom in some cases.
 It it crucial ? If so, how to replace with the setoid_ring
 equivalent ?

git-svn-id: svn+ssh://scm.gforge.inria.fr/svn/coq/trunk@15524 85f007b7-540e-0410-9357-904b9bb8a0f7
---
 test-suite/success/LegacyField.v | 76 ----------------------------------------
 1 file changed, 76 deletions(-)
 delete mode 100644 test-suite/success/LegacyField.v

(limited to 'test-suite')

diff --git a/test-suite/success/LegacyField.v b/test-suite/success/LegacyField.v
deleted file mode 100644
index df4da431f1..0000000000
--- a/test-suite/success/LegacyField.v
+++ /dev/null
@@ -1,76 +0,0 @@
-(************************************************************************)
-(*  v      *   The Coq Proof Assistant  /  The Coq Development Team     *)
-(* <O___,, *   INRIA - CNRS - LIX - LRI - PPS - Copyright 1999-2010     *)
-(*   \VV/  **************************************************************)
-(*    //   *      This file is distributed under the terms of the       *)
-(*         *       GNU Lesser General Public License Version 2.1        *)
-(************************************************************************)
-
-(**** Tests of Field with real numbers ****)
-
-Require Import Reals LegacyRfield.
-
-(* Example 1 *)
-Goal
-forall eps : R,
-(eps * (1 / (2 + 2)) + eps * (1 / (2 + 2)))%R = (eps * (1 / 2))%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-
-(* Example 2 *)
-Goal
-forall (f g : R -> R) (x0 x1 : R),
-((f x1 - f x0) * (1 / (x1 - x0)) + (g x1 - g x0) * (1 / (x1 - x0)))%R =
-((f x1 + g x1 - (f x0 + g x0)) * (1 / (x1 - x0)))%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-
-(* Example 3 *)
-Goal forall a b : R, (1 / (a * b) * (1 / 1 / b))%R = (1 / a)%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-
-(* Example 4 *)
-Goal
-forall a b : R, a <> 0%R -> b <> 0%R -> (1 / (a * b) / 1 / b)%R = (1 / a)%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-
-(* Example 5 *)
-Goal forall a : R, 1%R = (1 * (1 / a) * a)%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-
-(* Example 6 *)
-Goal forall a b : R, b = (b * / a * a)%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-
-(* Example 7 *)
-Goal forall a b : R, b = (b * (1 / a) * a)%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-
-(* Example 8 *)
-Goal
-forall x y : R,
-(x * (1 / x + x / (x + y)))%R =
-(- (1 / y) * y * (- (x * (x / (x + y))) - 1))%R.
-Proof.
-  intros.
-   legacy field.
-Abort.
-- 
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